QOJ.ac

QOJ

Time Limit: 15 s Memory Limit: 512 MB Total points: 100

#4344. rsrams

Statistics

给定一个长度 $n$ 的序列 $a_1,\dots,a_n$,你需要处理 $m$ 次查询,每次查询给出 $l,r$,对应答案为:

$\sum\limits_{L=l}^r \sum\limits_{R=L}^r \sum\limits_{c=1}^n c\cdot \left[R-L+1 < 2\sum\limits_{i=L}^R [a_i=c] \right]$。

其中 $[\mathrm{cond}]$ 表示如果括号中的条件表达式为真,则对应 $[\mathrm{cond}]=1$,否则对应 $[\mathrm{cond}]=0$。

输入格式

第一行两个整数 $n,m$;

第二行 $n$ 个整数 $a_1,\dots,a_n$

接下来 $m$ 行,每行两个整数 $l,r$ 表示一次查询。

输出格式

共 $m$ 行,每行一个整数,表示每次询问的答案。

样例数据

样例 1 输入

3 2
1 1 2
1 3
2 3

样例 1 输出

6
3

样例 2 ~ 3

见下发文件

子任务

注意,使用捆绑测试。

对于 $30\%$ 的数据,满足 $1\le n\le 10^3$,$1\le m\le 10^3$,$1\le a_i\le n$,$1\le l\le r\le n$。

对于 $60\%$ 的数据,满足 $1\le n\le 10^5$,$1\le m\le 10^5$,$1\le a_i\le n$,$1\le l\le r\le n$。

对于另外 $20\%$ 的数据,满足 $1 \le a_i \le 2$。

对于 $100\%$ 的数据,满足 $1\le n\le 10^6$,$1\le m\le 10^6$,$1\le a_i\le n$,$1\le l\le r\le n$。

About Issues

We understand that our problem archive is not perfect. If you find any issues with the problem, including the statement, scoring configuration, time/memory limits, test cases, etc.

You may use this form to submit an issue regarding the problem. A problem moderator will review your issue and proceed it properly.

STOP! Before you submit an issue, please READ the following guidelines:

  1. This is not a place to publish a discussion, editorial, or requests to debug your code. Your issue will only be visible by you and problem moderators. Other users will not be able to view or reply your issues.
  2. Do not submit duplicated issues. If you have already submitted one, please wait for an moderator to review it. Submitting multiple issues will not speed up the review process and might cause your account to be banned.
  3. Issues must be filed in English or Chinese only.
  4. Be sure your issue is related to this problem. If you need to submit an issue regarding another problem, contest, category, etc., you should submit it to the corresponding page.

Active Issues 0

No issues in this category.

Closed/Resolved Issues 0

No issues in this category.