QOJ.ac
QOJ
The 2nd Universal Cup Finals is coming! Check out our event page, schedule, and competition rules!
用户信息
KevinLikesCoding ♀
Rating
2050
Contribution
3
用户组
Default
格言
$\pi(n)=dp_{n,\pi(n^\frac{1}{3})}-\pi(n^\frac{1}{3})+1 -\sum_{p\in (n^\frac{1}{3},n^\frac{1}{2}]} \pi(\frac{n}{p})-\pi(p)+1$